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Sergio039 [100]
3 years ago
13

The sine and cosine of one of the acute angles in a right triangle are equal. What is the tangent of the angle?

Mathematics
1 answer:
Gnoma [55]3 years ago
4 0

Answer:

1

Step-by-step explanation:

Since tan(x) = sin(x)/cos(x), if sin(x) = cos(x) then tan(x) must be 1.

You can even reason that the acute angle is 45° and sin(x)=cos(x) = \frac12\sqrt2.

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41= 12d-7 solve for d
soldi70 [24.7K]

Answer:

d = 4

Step 1: Flip the equation.

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Step 3: Divide both sides by 12.

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Complete the equation so that it has infinitely many solutions.<br> 8x - 14 = 8x -
kati45 [8]

Answer:

8x-14=8x-14

Step-by-step explanation:

So if both the equations are the same, that means that any value of x put in the equation will equal itself, so that means that there are infinite solutions to the equation

If you try to solve this equation, this happens

8x-14=8x-14

add 14 to both sides

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divide by 8 both sides

x=x

This means that there are infinite solutions because any number could be x and it would still work

6 0
3 years ago
Read 2 more answers
If x+1 and x-1 are the factors of the polynomial ax^3 + x^2 - 2x +b,find the values of a and b
Nadusha1986 [10]

The polynomial remainder theorem says that dividing a polynomial p(x) by x-c leaves a remainder of p(c)=0 if x-c is a factor of p(x). In this case, check c=-1 and c=1.

a(-1)^3+(-1)^2-2(-1)+b=-a+b+3=0

a(1)^3+(1)^2-2(1)+b=a+b-1=0

From the first equation,

-a+b+3=0\implies a=b+3

and substituting into the second gives

(b+3)+b-1=0\implies2b+2=0\implies b=-1\implies a=2

3 0
3 years ago
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