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lorasvet [3.4K]
3 years ago
12

PLEASE HELP ME WITH THESE QUESTIONS!

Physics
1 answer:
olga_2 [115]3 years ago
8 0
The three scales are fahrenheit, celsius, and kelvin. 
<span><span>
Fahrenheit Celsius </span><span>Fahrenheit (F)F(F - 32) * 5/9
</span><span><span>Celsius (C or o)</span>(C * 9/5) + 32C
</span><span>Kelvin (K)(K - 273.15) * 9/5 + 32<span>K - 273.15

</span></span></span>One degree Celsius is a bigger unit of measurement than one degree Fahrenheit. One degree C equals 1.8 degrees F. 

<span>Normal body temp is 98.6 F, which converts to 37 C. If your temp increased 2 degrees F, it would be 100.6, which is a fairly mild fever. An increase of 2 degrees C is 39, or 102.2 F. Obviously, 102.2 is a higher fever than 100.6.</span><span>

</span>
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What is the radius of sun and earth?
dezoksy [38]

Radius of SUN =  695,700 km

Radius of EARTH =  6,371 km


6 0
3 years ago
A ball rolls at a speed of 6cm/s how far does the ball roll in 40 seconds ? ____cm
konstantin123 [22]
240 cm you do 6x 40 and should get 240cm
6 0
3 years ago
Ejercicio de la ley de coulumb
trapecia [35]

maratón de 16354 de 1635

4 0
3 years ago
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

8 0
4 years ago
A block is being pulled by a rope in a straight line across a horizontal floor which is non frictionless. The rope is pulling on
ikadub [295]

Answer:

60 N

Explanation:

We can answer the question by using Newton's third law, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

In this situation, we can identify the rope as object A, and the block as object B.

We are told that the rope exerts a force of 60 N on the block: if we apply Newton's third law, therefore, we can say that the block will also exert an equal (60 N) and opposite (in direction) force on the rope.

6 0
3 years ago
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