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ch4aika [34]
3 years ago
8

In addition to the conditions required for any solar eclipse, what must also be true in order for you to observe a total solar e

clipse?
Physics
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer: The umbra, which is the dark shadow wherein the Sun's light is completely blocked, must pass over where one is for that person to observe a total solar eclipse.

Explanation:

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Why do some scientists not use controlled experiments?
Leviafan [203]
Observational studies are a prime example. Observational data is more reflective of the real environments that scientists make their inferences to than controlled experiments. The disadvantage of observational studies is that the variability is far greater. <span />
7 0
4 years ago
Two blocks of masses 8 kg and 4.3 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them
oee [108]

Answer:

The velocity of other mass is 3.60 m/s.

Explanation:

Given that,

Mass of first block = 8 kg

mass of second block = 4.3 kg

Speed = 6.7 m/s

We need to calculate the speed of first mass

Using conservation of momentum

(m_{1}+m_{2})u=m_{1}v_{1}+m_{2}v_{2}

where, m₁ =mass of first block

m₂ =mass of second block

m₁ =mass of first block

v₂ =speed of second block

Put the value into the formula

8+4.3\times0=8\times v_{1}+4.3\times6.7

v_{1}=\dfrac{-4.3\times6.7}{8}

v_{1}=-3.60\ m/s

Negative sign represent the opposite direction of initial value.

Hence, The velocity of other mass is 3.60 m/s.

3 0
3 years ago
A small but measurable current of 1.2 10-10A exists in a copper wire whose diameter is 2.0 mm. Assume the current is uniform. (a
Rom4ik [11]

Q: A small but measurable current of 1.2×10⁻¹⁰A exists in a copper wire whose diameter is 2.0 mm. Assume the current is uniform. (a) Calculate the current density.

Answer:

3.82×10⁻⁵ A/m

Explanation:

Current density: This can be defined as the amount of charge passing through a conductor, per unit area, per unit time. The S.I unit of current density is A/m²

From the question above, the expression for current density is given as,

τ = I/A............... Equation 1

Where τ = current density of the copper wire, I = current flowing  through the copper wire, A = cross sectional area of the copper wire

But,

A = πd²/4................. Equation 2

Substitute equation 2 into equation 1

τ = 4I/(πd²)............ Equation 3

Given: I = 1.2×10⁻¹⁰ A, d = 2 mm = 2×10⁻³ m, π = 3.14

Substitute into equation 3

τ = 4(1.2×10⁻¹⁰)/[3.14×(2×10⁻³)²]

τ = (4.8×10⁻¹⁰)/(1.256×10⁻⁵)

τ = 3.82×10⁻⁵ A/m

5 0
3 years ago
Read 2 more answers
The magnetic field 40.0 cm away from a long, straight wire carrying current 2.00 A is 1.00μT. (a) At what distance is it 0.100μ
maw [93]

The distance should be 4m from the wire in order to get the magnetic field of 0.100μ .

  • The magnitude and direction of the magnetic field due to a straight  wire carrying current can be calculated using the previously mentioned Biot-Savart law. Let "I" be the current flowing in a straight line and "r" be the distance. Then the magnetic field produced by the wire at that particular point is given by  B=\frac{u_0I}{2\pi r}  ...(1)
  • Since the wire is assumed to be very long, the magnitude of the magnetic field depends on the distance of the point from the wire rather than the position along the wire.

It is given that magnetic field 40.0 cm away from a straight wire is  1.00μT having  current 2.00 A .

From equation (1)  magnetic field 40.0 cm = 0.4m away from a straight wire is 1.00μT which is given by    1.00=\frac{u_0I}{2\pi \times0.4}      .....(2)

From equation (1)  magnetic field 'r' m away from a straight wire is 0.100μT which is given by    0.100=\frac{u_0I}{2\pi \times r}       ...(3)

On dividing equation (2) by (3) , we get

             \frac{1}{0.1} =\frac{r}{0.4} \\\\r=4m

Learn more about magnetic field here :

brainly.com/question/27939568

#SPJ4

 

4 0
2 years ago
Whu is it important to mave regular supervision of weights and measurements in the market​
pentagon [3]

Answer:

Hope the answer helped you. if yes pls follow me

Explanation:

the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.

5 0
3 years ago
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