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Feliz [49]
3 years ago
12

I need help plz help me​

Physics
1 answer:
kirza4 [7]3 years ago
8 0

Answer:ghhg

Explanation:

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Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
Read 2 more answers
Subject- Science <br>Grade- 6th<br>please help me with hw. Thank you!<br>​
velikii [3]

Answer:

b. they get blown in from colder or warmer areas.

3 0
2 years ago
Read 2 more answers
A dairy farmer notices that a circular water trough near the barn has become rusty and now has a hole near the base. The hole is
Crazy boy [7]

Answer:

v=1.93m/s

Explanation:

From the concept of fluids mechanics we know that if a tank has a hole at the bottom, the equation that we need to use is:

v=\sqrt{2gh}

Since we know gravity and its hight

v=\sqrt{2*(9.81m/s^{2})(0.19m) }=1.93m/s

5 0
3 years ago
gas has a volume of 185 ml and pressure of 310 mm hg. The desiered volume is 74.0 ml. What is the required new pressure
Mamont248 [21]

Answer:

The required new pressure is 775 mm hg.

Explanation:

We are given that gas has a volume of 185 ml and a pressure of 310 mm hg. The desired volume is 74.0 ml.

We have to find the required new pressure.

Let the required new pressure be '\text{P}_2'.

As we know that Boyle's law formula states that;

                    P_1 \times V_1 = P_2 \times V_2

where, P_1 = original pressure of gas in the container = 310 mm hg

           P_2 = required new pressure

            V_1 = volume of gas in the container = 185 ml

            V_2 = desired new volume of the gas = 74 ml

So,  P_2 = \frac{P_1 \times V_1}{V_2}  

       P_2 = \frac{310 \times 185}{74}

            =  775 mm hg

Hence, the required new pressure is 775 mm hg.

7 0
3 years ago
Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,
makkiz [27]

The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/s^{2}.

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e V^{2} = U^{2} ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

V^{2} = U^{2} - 2as

0 = (4)^{2} - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \frac{16}{0.402}

  = 39.801

a = 39.80 m/s^{2}

Therefore Paola's acceleration is 39.80 m/s^{2}.

Visit: brainly.com/question/17493533

7 0
2 years ago
Read 2 more answers
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