If you call 
the mass of the ant and 
the load, we have the equation
In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.
Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:
Answer:
The equation solved for V is m/d=V
The answer is <span> π, any number divided by 1 is the same number it was</span>
A=-.25+6.7t, s=.75+4.5t when Amir catches up a=s so:
-.25+6.7t=.75+4.5t add .25 to both sides
6.7t=1+4.5t subtract 4.5t from both sides
2.2t=1 divide both sides by 2.2
t=10/22 hr
t≈0.45 hr (to nearest hundredth)
Answer:
a and b.
Step-by-step explanation:
I’ll explain by giving an example.
Let’s say that: a=3;b=4;c=5; => they all are consecutive -> their sum is 12.
=> if we use a) n=3 => 3*n+3=3*3+3=12 => correct.
b) n+(n+1)+(n+2)= 3+4+5=12=> correct.
c)n+2n+3n=3+6+9=18=>incorrect.
d)3n=3*3=9=>incorrect.
