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NikAS [45]
3 years ago
8

Why is gasoline so flammable

Physics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0
Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.




Hope this helps




I looked this up




Don't forget to rate and thanks me
liq [111]3 years ago
7 0
It is flammable because of the low flashpoint. Gasoline's flashpoint is -40 degrees Fahrenheit, which essentially means that the vapors released into the oxygenated air can be lit ablaze in low temperatures.
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A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken
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Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

v^{2} = u^{2} + 2as

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

0^{2} = 20^{2} + 2(10)s

Rearrange for s

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\frac{-400}{20} =s

s = -20 (The negative is just showing direction, it can be ignored for now)

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Use a different equation to find the time taken

s = vt - \frac{1}{2} at^{2}

Substitute in the values we have

-20=(0)t - \frac{1}{2} (10)t^{2}

Rearrange for t

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\frac{-20}{-5} =t^{2}

4 = t^{2}

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The time taken to reach 20m is 2 seconds

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