One liter of water weighs about 10 n. suppose a 3-liter container is filled with 266N of mercury and then lowered into a contain
1 answer:
Answer:
30 N
Explanation:
The buoyant force acting on an object is an upward force exerted by the fluid in which the object is immersed.
The magnitude of the buoyant force is equal to the weight of the fluid displaced by the object, mathematically:
where
is the density of the fluid
V is the volume of fluid displaced
g is the acceleration due to gravity
The formula can be written also as
where m is the mass of fluid displaced.
In this problem, the 3-Liter container filled with mercury is completely submerged in the water: this means that the volume of water displaced is
V = 3 L
We also know that 1 L of water weights about 10 N, so the weight of 3 L of water is
And therefore, this is the buoyant force acting on the container: 30 N.
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Answer : The change in enthalpy of the reaction is, -310 kJ
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given main reaction is,
The intermediate balanced chemical reaction will be,
(1)
(2)
(3)
Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :
(1)
(2)
(3)
The expression for enthalpy of formation of will be,
Therefore, the change in enthalpy of the reaction is, -310 kJ