Question

One liter of water weighs about 10 n. suppose a 3-liter container is filled with 266N of mercury and then lowered into a container of water. Assuming the container is completely submerged, what is the buoyant force acting on it?
how do you get the answer to this problem?

Answer 1

Answer:

30 N

Explanation:

The buoyant force acting on an object is an upward force exerted by the fluid in which the object is immersed.

The magnitude of the buoyant force is equal to the weight of the fluid displaced by the object, mathematically:

$B=\rho Vg$

where

$\rho$ is the density of the fluid

V is the volume of fluid displaced

g is the acceleration due to gravity

The formula can be written also as

$B=mg$

where m is the mass of fluid displaced.

In this problem, the 3-Liter container filled with mercury is completely submerged in the water: this means that the volume of water displaced is

V = 3 L

We also know that 1 L of water weights about 10 N, so the weight of 3 L of water is

$mg=3\cdot 10 = 30 N$

And therefore, this is the buoyant force acting on the container: 30 N.