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Ira Lisetskai [31]
3 years ago
7

To determine whether a graph of a relation is also a function, Shayla declares that the y-axis is a vertical line and counts the

number of times that the graph intersects the y-axis. If the graph has exactly one y-intercept, Shayla concludes that the graph shows a function. In all other cases, she declares that it is not a function.
Is Shayla applying the vertical line test correctly?
Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

No.

Step-by-step explanation:

The function is any equivalence relation in which there is only one output for every input. This means that the domain must be exhausted in order to gain all the elements of the range and each element of domain gets mapped to only one of the elements of the range. Vertical line test is used to determine whether a graph is a function or not. This test requires that vertical lines parallel to y-axis and including y-axis be drawn on the graph to see that each vertical line intersects the graph only once. This must be true for all the elements of the domain. Therefore, vertical line test requires to draw numerous vertical lines other than the y-axis since the definition of the function requires that. In short, mathematically, there will be a need for infinite number of vertical lines to perform the test. Therefore, Shayla is not applying the vertical line test correctly!!!

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Explain why leg leg(LL) theorem is the same as the side angle side postulate
Sveta_85 [38]
Recall that the LL theorem, as well as the LA theorem, both apply only to right-triangles.

now, in the LL, if a right-triangle has congruent Legs with another, both right-triangles are congruent.

in the LA, if a right-triangle has one Leg and one Angle congruent with another right-triangle, then they're congruent.

well, in the LA, once you have a Leg and then an Angle touching that Leg, the angle is also touching another Leg, since it is an angle and is cornered by two Legs.  The second Leg touched or stemming from that Angle, can only be of one possible length, because the first Leg and the Angle will constrain it to be of certain length.

and that is true for both triangles, and since both triangles will have a second Leg constrained to be a certain length, because of LA, then a second Leg will also be congruent on both right-triangles, so the theorem kinda becomes LAL theorem, Leg Angle Leg, but we can just do away with the Angle part and call it LL.
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3 years ago
Find the measure of
Bingel [31]

Answer:

I feel like its 75 degrees and also are u in 8th and have u done power quotient and product rule before if so I need help

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3 years ago
A department store surveyed 428 shoppers, and the following information was obtained: 216 shoppers made a purchase, and 294 were
Maurinko [17]

Answer:

(a) 169

(b) 341

(c) 125

(d) 87

Step-by-step explanation:

Consider the Venn diagram below.

The total number of shoppers surveyed is, <em>N</em> = 428.

Number of shoppers who made a purchase, <em>n</em> (P) = 216

Number of shoppers who were satisfied with the service they received,

<em>n</em> (S) = 294

Number of shoppers who made a purchase but were not satisfied with the service, n(S^{c}\cap P) = 47

(a)

The number of shoppers who made a purchase and were satisfied with the service = <em>n</em> (S ∩ P)

             n(S\cap P)=n(P)-n(S^{c}\cap P)\\=216-47\\=169

(b)

The numbers of shoppers who made a purchase or were satisfied with the service = <em>n</em> (P ∪ S)

               n(P\cup S)=n(P)+n(S)-n(P\cap S)\\=n(P)+n(S)-n(S\cap P)\\=216+294-169\\=341

(c)

The numbers of shoppers who were satisfied with the service but did not make a purchase = n(S\cap P^{c})

n (S\cap P^{c} ) = n (S) - n (S \cap P)\\=294-169\\=125

(d)

The number of shoppers who were not satisfied and did not make a purchase  = n(S^{c}\cap P^{c})

n(S^{c}\cap P^{c})=N-n(S\cup P)\\=N-n(P\cup S)\\=428-341\\=87

6 0
3 years ago
Write an equivalent expression for n times a using only addition
trasher [3.6K]
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4 years ago
Use the discriminant to determine the number and type of solutions for the following equation. 12x2 + 10x + 5 = 0
Paul [167]
Discriminant D is given by:
D=b²-4ac
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D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square)  two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0

Answer is: 
<span>A two irrational solutions </span>
4 0
4 years ago
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