Maturation, further growth
Answer:
Kc = [CO][Cl₂]/[COCl].
Kp = P(CO)P(Cl₂)/P(COCl).
Explanation:
For the balanced reaction:
COCl₂(g) ⇄ CO(g) + Cl₂(g).
The equilibrium constant can be expressed as concentration equilibrium constant (Kc) or pressure equilibrium constant (Kp).
The equilibrium constant is the ratio of the product of products concentrations to the product of the reactants concentrations.
Kc = [CO][Cl₂]/[COCl].
Kp = P(CO)P(Cl₂)/P(COCl).
<span>chemically stable = Full octet outer shell = <u>8 valence electrons</u></span>
To find this answer you take the mass of the carbon in the compound and divide it by the mass of the entire compound, the one closest to 40% is the correct answer.
I will do hexose for you and you can do the rest of them
mass hexose = 6*12 + 12*1 + 6*16 = 72 + 12 + 96 = 180
mass C in hexose = 6 * 12 = 72
% C in hexose = 72/180 * 100% = 40% (This may be your answer unless you have multiple answers for this one)
2.61 kilojoules of heat would be liberated by the condensation of 5.00 g of acetone
Explanation:
To convert grams into moles
![moles = grams \times \frac{1 mole}{grams}](https://tex.z-dn.net/?f=moles%20%3D%20grams%20%5Ctimes%20%5Cfrac%7B1%20mole%7D%7Bgrams%7D)
We have 5.00 g acetone
![moles = 5 \times \frac{1}{58.1}](https://tex.z-dn.net/?f=moles%20%3D%205%20%5Ctimes%20%5Cfrac%7B1%7D%7B58.1%7D)
![moles = 0.0861](https://tex.z-dn.net/?f=moles%20%3D%200.0861)
Heat liberated = moles
heat of vapourization
=0.0861 mol x 30.3 kJ/mol
= 2.61 kJ
Therefore, 2.61 kilojoules of heat would be liberated by the condensation of 5.00 g of acetone