For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as
pH=3.95
<h3>What is the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer?</h3>
Generally, the equation for the Hendersons equation is mathematically given as
pH=pKa+log(SALT)/(ACID)
Where
moles of (NaCOOH)=100*0.05/1000
moles of (NaCOOH)=0.05moles
and formic acid
moles of formic acid=100*0.05/1000
moles of formic acid=0.05moles
Therefore
pKa=-logka
pKa=1.4*10*3.77
pH=3.77+log{0.06/0.04}
pH=3.95
In conclusion, the pH is
pH=3.95
Read more about pH
brainly.com/question/1503669
Answer:
3 mol Cl₂/2 mol AlCl₃ (three over two)
Step-by-step explanation:
Start with the balanced equation"
2Al + 3Cl₂⟶ 2AlCl₃
The steps in the calculation are
mass of AlCl₃ ⟶ moles of AlCl₃⟶ moles of Cl₂ ⟶ mass of Cl₂
The critical step is the <em>conversion of moles</em>.
You multiply the moles of AlCl₃ by a <em>conversion factor</em> to get moles of Al:
Moles of AlCl₃ × conversion factor = moles of Al.
The conversion factor is <em>the molar ratio</em>, and it uses the coefficients of the formulas in the balanced equation.
It is either (2 mol AlCl₃/3 mol Cl₂) or (3 mol Cl₂/2 mol AlCl₃).
You choose the one that has the desired units of the answer in the numerator.
We choose the second option, because it has the correct units.
For example,
Notice how the units "mol AlCl₃" cancel and the correct units appear in the answer.
If we had used the other conversion factor, we would have gotten the wrong units.
Water will have higher surface tension.
Explanation:
There are strong hydrogen bonds and strong intermolecular forces present in water. Water is polar in nature that is why surface tension is present in it. The force of attraction between the particles is the main factor for surface tension.
The cohesion force in the liquid causes surface tension.
Since the other substance is acetone which does not form strong intermolecular forces hence it has low value of surface tension. They have low cohesive forces and get stick to the surface and are spilled instead of attaining minimal volume.
Answer:
The answer to your question is Cm = 2.093 J/kg°C
Explanation:
Data
mass metal = mass of water
Δ water = 5°
Δ metal = 10°
Cm = ?
Cw = 4.186 J/Kg°C
Formula
for metal for water
mCmΔTm = mCwΔTw
Cancel mass of metal
Cm ΔTm = CwΔTw
solve for Cm
Cm = (CwΔTw) / ΔTm
Substitution
Cm = (4.186 x 5) / 10
Simplification
Cm = 20.93 / 10
Result
Cm = 2.093 J/kg°C