Determine the empirical formula of a compound containing 63.50 % silver, 8.25 % nitrogen, and the remainder oxygen.
1 answer:
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11.48-gram of are needed to produce 6.75 Liters of
gas measured at 1.3 atm pressure and 298 K
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1.3 atm
V= 6.75 Liters
n=?
R=
T=298 K
Putting value in the given equation:
Moles = 0.3588 moles
Now,
Mass= 11.48 gram
Hence, 11.48-gram of are needed to produce 6.75 Liters of
gas measured at 1.3 atm pressure and 298 K
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Answer:
1.48×10²⁴ Cu atoms
Explanation:
For this question you need to use Avogadro's number 6.022×10²³atoms.
2.45 moles of Cu ×= 1.47539×10²⁴ atoms.
The moles cancel out so you are left with atoms.
Since there are 3 significant figures in the question there should be 3 significant figures in your answer, which is 1.48×10²⁴ Cu atoms.