All categories

2 years ago

Calculate the molar mass of B(NO3)3 ?

Chemistry

1 answer:

Stella [2.4K]2 years ago

7 0

The molar mass of B(NO₃)₃ - Boron nitrate : 196.822 g/mol

<h3>Further explanation</h3>

In stochiometry therein includes

<em>Relative atomic mass (Ar) and relative molecular mass / molar mass (M) </em>

So the molar mass of a compound is given by the sum of the relative atomic mass of Ar

M AxBy = (x.Ar A + y. Ar B)

The molar mass of B(NO₃)₃ - Boron nitrate :

M B(NO₃)₃ = Ar B + 3. Ar N + 9.Ar O

M B(NO₃)₃ = 10.811 + 3. 14,0067 + 9. 15,999

M B(NO₃)₃ = 196.822 g/mol

You might be interested in

How can you determine the quantities of reactants and products in a chemical reaction

prohojiy [21]

Use the balanced equation.

5 0

3 years ago

? Question

masya89 [10]

Answer:

Gravity drives all mass wasting.

Explanation:

Mass wasting can be defined as the process of wasting away of earth's outer crust. This movement is also known as slope movement that causes large rock, soil, and debris to move downward, a force driven by gravity.

The term is often used interchangeably with landslide yet it is different. It is also known as mass movement as is cause massive downslope movement of rock, regolith, snow, ice, and-the-like on the earth's outer crust.

<u>All these movements are driven mainly by gravity. Gravity consantly tries to pull the rocks and soil down the slope but the resisting power. also known as shear strength, of moutains helps them to deny the gravitional force.</u>

Thus from the given options the statement that can be said to be true about mass wasting is that mass wasting is driven by gravity. So, the correct option is C.

4 0

3 years ago

When backpacking in the wilderness, hikers often boil water to sterilize it for drinking. Suppose that you are planning a backpa

Pavlova-9 [17]

Answer:

2.104 L fuel

Explanation:

Given that:

Volume of water = 35 L = 35 × 10³ mL

initial temperature of water = 25.0 ° C

The amount of heat needed to boil water at this temperature can be calculated by using the formula:

$q_{boiling} = mc \Delta T$

where

specific heat of water c= 4.18 J/g° C

$q_{boiling} = 35 \times 10^{3} \times \dfrac{1.00 \ g}{1 \ mL} \times 4.18 \ J/g^0 C \times (100 - 25)^0 C$

$q_{boiling} = 10.9725 \times 10^6 \ J$

Also; Assume that the fuel has an average formula of C7 H16 and 15% of the heat generated from combustion goes to heat the water;

thus the heat of combustion can be determined via the expression

$q_{combustion} =- \dfrac{q_{boiling}}{0.15}$

$q_{combustion} =- \dfrac{10.9725 \times 10^6 J}{0.15}$

$q_{combustion} = -7.315 \times 10^{7} \ J$

$q_{combustion} = -7.315 \times 10^{4} \ kJ$

For heptane; the equation for its combustion reaction can be written as:

$C_7H_{16} + 11O_{2(g)} -----> 7CO_{2(g)}+ 8H_2O_{(g)}$

The standard enthalpies of the products and the reactants are:

$\Delta H _f \ CO_{2(g)} = -393.5 kJ/mol$

$\Delta H _f \ H_2O_{(g)} = -242 kJ/mol$

$\Delta H _f \ C_7H_{16 }_{(g)} = -224.4 kJ/mol$

$\Delta H _f \ O_{2{(g)}} = 0 kJ/mol$

Therefore; the standard enthalpy for this combustion reaction is:

$\Delta H ^0= \sum n_p\Delta H^0_{f(products)}- \sum n_r\Delta H^0_{f(reactants)}$

$\Delta H^0 =( 7 \ mol ( -393.5 \ kJ/mol) + 8 \ mol (-242 \ kJ/mol) -1 \ mol( -224.4 \ kJ/mol) - 11 \ mol (0 \ kJ/mol))$

$\Delta H^0 = (-2754.5 \ \ kJ - 1936 \ \ kJ+224.4 \ \ kJ+0 \ \ kJ)$

$\Delta H^0 = -4466.1 \ kJ$

This simply implies that the amount of heat released from 1 mol of C7H16 = 4466.1 kJ

However the number of moles of fuel required to burn $7.315 \times 10^{4} \ kJ$ heat released is:

$n_{fuel} = \dfrac{q}{\Delta \ H^0}$

$n_{fuel} = \dfrac{-7.315 \times 10^{4} \ kJ}{-4466.1 \ kJ}$

$n_{fuel} = 16.38 \ mol \ of \ C_7 H_{16$

Since number of moles = mass/molar mass

The mass of the fuel is:

$m_{fuel } = 16.38 mol \times 100.198 \ g/mol}$

$m_{fuel } = 1.641 \times 10^{3} \ g$

Given that the density of the fuel is = 0.78 g/mL

and we know that :

density = mass/volume

therefore making volume the subject of the formula in order to determine the volume of the fuel ; we have

volume of the fuel = mass of the fuel / density of the fuel

volume of the fuel = $\dfrac{1.641 \times 10^3 \ g }{0.78 g/mL} \times \dfrac{L}{10^3 \ mL}$

volume of the fuel = 2.104 L fuel

3 0

3 years ago

The process where all chemical reactions within organisms enable them to maintain life is known as

bulgar [2K]

The answer is the option d. metabolism.

Metabolism is the set of the chemical reactions that happens in the organism to transform nutrients (food) in energy and the products that conform the cells and all the constituents of the body.

5 0

3 years ago

Read 2 more answers

1. A rock with a mass of 66.5g<br>occupies 23.0 cm. Density?

telo118 [61]

Answer:

2.89 g/cm^3

Explanation:

Since density equals mass over volume (or also seen as $d=\frac{m}{v}$ ), simply divide 66.5 grams by 23.0 cm. This will output an answer of 2.89 g/cm^3.

7 0

3 years ago

Calculate the molar mass of B(NO3)3 ?​

Calculate the molar mass of B(NO3)3 ?