3 1/6 = 19/6
2 1/9 = 19/9
19/6 / 19/9 = 19*9/19*6 = 9/6 = 3/2
This equation has only one solution
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Answer:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
99% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Answers: (y = 2) and (x = 1)
Steps: