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3 years ago

Which symbol correctly compared the two fractions 2/3 and 4/6

Mathematics

2 answers:

Aliun [14]3 years ago

7 0

Remark

First of all youhave to know the values of each of the fractions. Then you can compare them.

Solution

2/3 = 0.666667 Your calculator will tell you this value.

4/6 = 0.666667 This is something that also comes the calculator

Since both of them are the same, you should show it as

2/3 = 4/6

RSB [31]3 years ago

6 0

They both equal so symbol is "=" they have LCM of 3 .

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What is the solution to the system of equations below?

Andre45 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

$y=-6x-10$

$y=-3x-21$

solving the system of the equations

Arrange the equation variables for elimination

$\begin{bmatrix}y+6x=-10\\ y+3x=-21\end{bmatrix}$

$y+3x=-21$

$-$

$\underline{y+6x=-10}$

$-3x=-11$

$\begin{bmatrix}y+6x=-10\\ -3x=-11\end{bmatrix}$

solve

$-3x=-11$

Divide both sides by -3

$\frac{-3x}{-3}=\frac{-11}{-3}$

$x=\frac{11}{3}$

$\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=\frac{11}{3}$

$y+6\cdot \frac{11}{3}=-10$

$y=-32$

Therefore, the solutions to the system of the equations are:

$y=-32,\:x=\frac{11}{3}$

But, it seems none of the options is true.

8 0

3 years ago

Read 2 more answers

Write P on the space provided for the two ratios are proportion and NP if it is not

balu736 [363]

Answer:

1 p

2 np

3 np

4 p

5 p

hoped that helped

5 0

2 years ago

g An urn contains 150 white balls and 50 black balls. Four balls are drawn at random one at a time. Determine the probability th

xxTIMURxx [149]

Answer:

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

Step-by-step explanation:

For sampling with replacement, we use the binomial distribution. Without replacement, we use the hypergeometric distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Sampling with replacement:

I consider a success choosing a black ball, so $p = \frac{50}{150+50} = \frac{50}{200} = 0.25$

We want 2 black balls and 2 white, 2 + 2 = 4, so $n = 4$ , and we want P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.25)^{2}.(0.75)^{2} = 0.2109$

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Sampling without replacement:

150 + 50 = 200 total balls, so $N = 200$

Sample of 4, so $n = 4$

50 are black, so $k = 50$

We want P(X = 2).

$P(X = 2) = h(2,200,4,50) = \frac{C_{50,2}*C_{150,2}}{C_{200,4}} = 0.2116$

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

3 0

2 years ago

The weights of steers in a herd are distributed normally. The variance is 40,00040,000 and the mean steer weight is 1400lbs1400

Alex777 [14]

Answer:

$P(1739$

(Correct to 4 decimal places)

Step-by-step explanation:

The probability of a continuous normal variable X found in a particular interval [a, b] is the area under the curve bounded by x=a and x=b and is given by:

$P(a$

where

$f(X)=\frac{1}{\sigma \sqrt{2 \pi} }e^{-\frac{1}{2} (\frac{x-u}{ \sigma} )^2}$

$f(X)=\frac{1}{200 \sqrt{2 \pi} }e^{-\frac{1}{2} (\frac{x-1400}{ 200} )^2}\\=\frac{1}{200 \sqrt{2 \pi} }e^{- \frac{(x-1400)^2}{ 80000}\\$

$P(1739$

Using a calculator,

$P(1739$

5 0

3 years ago

Read 2 more answers

the measurement of one angle of a right angle is 42 degrees what is the measurement of the third angle

kogti [31]

The angles of a triangle all add up to 180°. In fact, it can be generalized that the sum of the interior angles of an n-sided polygon is equal to 180°(n–2).

A right triangle must have a right angle, which is equal to 90°. If the other angle is 42°, that means that we can find the third angle by subtracting 90° + 42° from 180°.

x = 180° – (90° + 42°) = 48°

8 0

3 years ago