1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RUDIKE [14]
2 years ago
15

A ribbon is 4 m long. How many pieces each 30 cm long can be cut from the ribbon?​

Mathematics
2 answers:
Simora [160]2 years ago
7 0

Answer:

13

Step-by-step explanation:

4 meters is equal to 400 centimeters.

400/30 =  13 1/3

You don't want partial pieces, so your answer is 13

EleoNora [17]2 years ago
5 0

Answer:

13 pieces

Step-by-step explanation:

First we convert 4m into cm :

1m = 100cm

4m = 400cm

Now we need to figure out how many 30s go into 400 :

400 ÷ 30 = 13 remainder 10

So 13 pieces can be cut from the ribbon

Hope this helped and have a good day  

You might be interested in
Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples
zheka24 [161]

Answer: a. 0.40   b. 0.23  c . 0.435   d . 0.25

Step-by-step explanation:

                                   melanin      content    Total

                                            high   low

moisture   high                     13      10                23

content    low                       47      30                77

 Total                                   60      40              <u> </u><u>100</u>

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)=\dfrac{40}{100}=0.40

b) Total skin samples has high moisture content = 13+10=23

P(B) =\dfrac{23}{100}=0.23

c) A ∩ B =  Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) =\dfrac{10}{100}=0.10

Using conditional probability formula , P (A|B)=\dfrac{P(A\cap B)}{P(B)}

P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435

d)  P (B|A)=\dfrac{P(A\cap B)}{P(A)}

P (B|A)=\dfrac{0.10}{0.40}=0.25

8 0
3 years ago
A rectangle has an area of 18cm^2. The lengths of the sides are whole numbers. How long can each of the sides be? Give all the e
babymother [125]

Answer:

Area of rectangle = l x b

18 = l x b

Factors of 18 =

1 x 18 = 18

2 x 9 = 18

3 x 6 = 18

So each of the sides can be either 1cm and 18 cm, 2cm and 9cm and 3cm and 6cm.

6 0
3 years ago
Rewrite this expression as a single power 12^5•12^7/-12^4
9966 [12]

Answer:-12^8

Step-by-step explanation:

4 0
3 years ago
Vicky downloaded to apps on her iPhone the first app was $599 and the second Apple was 14. $33 how much did Vicky spend on the a
Gala2k [10]

Answer:

573.33

Step-by-step explanation:

599+14.33

= 573.33

(if rounding then its  600+14.33) = 614.33

5 0
2 years ago
Twice a number x exceed 5 at least by 4. find the possible value of x.
salantis [7]

Answer:

5?

Step-by-step explanation:

2x › 5 (buy at least 4)

so you can just start plugging numbers in.

I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.

5 0
3 years ago
Read 2 more answers
Other questions:
  • Factor by grouping.
    11·2 answers
  • An airplane travels at an average speed of 250 mph for 3 hours.
    5·2 answers
  • In complete sentence explain the process of mitosis<br><br> in your own words plz
    9·2 answers
  • What property would be used to solve 6x=72
    6·2 answers
  • Whats the answer to x 2x x -16
    15·1 answer
  • I have 2 fewer sides than a polygon
    9·1 answer
  • Fill in the book value at the end of year 1 under each depreciation method when residual value is $36,000 and useful life is 4 y
    13·1 answer
  • Work out the percentage discount offered with the family ticket option
    12·1 answer
  • PLEASE HELP!! 50 POINTS!<br> Answer the question in the picture.
    12·2 answers
  • 2 1/2x + 1/4 + 3/4x = 1/8
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!