hola ny yo no puedo y quiero la respuesta
Answer:
no, not proportional
Step-by-step explanation:
set up a proportion and see if cross-products are equal:
8/3 = 14/6
cross-multiply:
(8)(6) ≠ (14)(3)
48 ≠ 42
Answer: (-20,-4)
First, you substitute y into the first equation to get 0.01x - 0.3(0.1x - 2) = 1
You then distribute the 0.3 to what is inside the parentheses to get 0.01x-0.03x+0.6=1
(Note: the 0.6 is positive because two negatives multiplied equal a positive)
Now you combine like terms to get -0.02x+0.6=1
Subtract 0.6 from both sides of the equal sign to get -0.02x=0.4
Divide each side by -0.02 to get x=-20
Now plug in -20 to y=0.1x-2 to get y=-4
This gives you the answer (-20,-4)
Answer:
The value of k that makes the relationship shown in the table below proportional is ![\mathbf{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7B1%7D%7B2%7D%7D)
Step-by-step explanation:
The relation is proportional if ![y=kx \:or\:k=\frac{y}{x}](https://tex.z-dn.net/?f=y%3Dkx%20%5C%3Aor%5C%3Ak%3D%5Cfrac%7By%7D%7Bx%7D)
Putting values of x and y to find k.
For x =2 and y =1 k is: ![k=\frac{y}{x}=\frac{1}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7By%7D%7Bx%7D%3D%5Cfrac%7B1%7D%7B2%7D)
For x =4 and y =2 k is: ![k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7By%7D%7Bx%7D%3D%5Cfrac%7B2%7D%7B4%7D%20%3D%5Cfrac%7B1%7D%7B2%7D)
For x =6 and y = 3 k is: ![k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7By%7D%7Bx%7D%3D%5Cfrac%7B3%7D%7B6%7D%20%3D%5Cfrac%7B1%7D%7B2%7D)
For x = 8 and y = 4 k is: ![k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7By%7D%7Bx%7D%3D%5Cfrac%7B4%7D%7B8%7D%20%3D%5Cfrac%7B1%7D%7B2%7D)
For x =10 and y = 5 k is: ![k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7By%7D%7Bx%7D%3D%5Cfrac%7B5%7D%7B10%7D%20%3D%5Cfrac%7B1%7D%7B2%7D)
So, The value of k that makes the relationship shown in the table below proportional is ![\mathbf{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7B1%7D%7B2%7D%7D)