Suppose a normal distribution has a mean of 79 and a standard deviation of 7. What is P(x< or = to 72)?
1 answer:
Answer:
P( Z <= -1) = 0.1587
Step-by-step explanation:
ok, mean u = 79
s = 7
find P( x <= 72)
P( (x - 79)/7 <= (72 - 79)/7 ) = ?
P( Z <= -1) = 0.1587 from Z-scores table
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