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Anon25 [30]
3 years ago
12

Given f (x) = 3 x minus 1 and g (x) = 2 x minus 3, for which value of x does g (x) = f (2)?

Mathematics
2 answers:
dangina [55]3 years ago
8 0

Answer:

x=4

Step-by-step explanation:

so I plugged in each answer to find which would make g(x)=f(2)

for f(2) you get f(2)= 3(2) -1

f(2)= 6-1 so f(2) is 5

using that plug in each answer into the G equation to get 5 out of it. i used 4

g(4)= 2(4) -3

g(4)= 8-3

g(4)=5

ta da the answer is x=4

hope this is helpful

antoniya [11.8K]3 years ago
5 0

Answer:

X = there and halve

3(1/2)

Step-by-step explanation:

F(x) =3x -2

g(x )= 2x-3

F(2) = 3(2) - 2

= 6-2

= 4

So the value of x that can make g(x) = 4

4= 2x-3

7 = 2x

X= 7/2

X = 3 1/2

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Step-by-step explanation:

4+2.5+1+...-33.5

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c.d. d=2.5-4=-1.5

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-37.5=(n-1)(-1.5)

n-1=(-37.5)/(-1.5)=25\\n=25+1=26\\n=26\\S_{26}=\frac{n}{2} (a+l)\\=\frac{26}{2} (4-33.5)\\=13(-29.5)\\=-383.5

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If we do this on the calculator, it's around 9.36 square kilometers, so our estimate was good.

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Read 2 more answers
Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: u_{x x}+u_{y y}=0

  • We must determine whether a given function is the solution to a given Laplace equation.
  • If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) u=e^{-x} \cos y-e^{-y} \cos x

Differentiate with respect to x as follows:

u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x

Differentiate with respect to y as follows:

u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x

Supplement the values in the given Laplace equation.

e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0

The given function in this case is the solution to the given Laplace equation.

(2) u=\sin x \cosh y+\cos x \sinh y

Differentiate with respect to x as follows:

u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y

Differentiate with respect to y as follows:

u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y

Substitute the values to obtain:

-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

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