9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
I believe it's C.
(Hint: y=mx+b)
M is Slope and B is Y-Intercept.
Mark will swim 182.88 meters
Answer:
x = 5√2
Step-by-step explanation:
The triangle on the right is a special right triangle, so we know that the adjacent side to 60° is 5. Since the left triangle is a 45-45-90, the hypotenuse is the leg times √2, so the value of x is 5√2
