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3 years ago

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HELP FIRST GET BRAINLLEST Measure the difference between the lower quartile of Data Set A and the lower quartile of Data Set B.

Round to the nearest tenth when performing all operations.

1 answer:

sergeinik [125]3 years ago

4 0

Answer:

29

Step-by-step explanation:

To find the lower quartile you need to split it into 2 by finding the median

Set A: 73, 75, 79, 81, 84, 85

Set B: 47, 49, 51, 51, 55, 56

Now you have to find the median of each

A: 80

B: 51

Lastly, you subtract and get 29

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Help!!! Find the measure of the arc or angle indicated.

Serhud [2]

Answer:

77°

Step-by-step explanation:

m∠QDC = 1/2(mQB + mBC)

5x + 17= 1/2( 4x - 6 + 9x + 4)
10x + 34 = 13x - 2
13x - 10x = 34 + 2
3x = 36
x = 12

m∠QDC = 5*12 + 17 = 77

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3 years ago

4/5+ unknown number =14/15

prohojiy [21]

Answer:

The unknown number is 2/15.

Step-by-step explanation:

4/5+x=14/15

x=14/15-4/5

x=14/15-12/15

x=2/15

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3 years ago

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F(x) = 2x2 - 5<br> and<br> g(x) = 5x + 7<br> Find<br> f(g(x)) = [ ? ]x2 + [ ]x +

lbvjy [14]

Answer:10x^2 -18

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3 years ago

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Step-by-step explanation:

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3 years ago

et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe

Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation $f(x)=x+\lvert 2x-3 \rvert=12$ can be solved as follows:

$x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}$

$\lvert 2x-3 \rvert =12-x$

$2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)$

$3x=15\,\,\text{or}\,\,\x=-9$

Then, the solutions of the equation are $x=5, x=-9$ .

Now, if $g(x)=5x-3+\lvert x+4\rvert$ , we can solve the equation $g(a)=4a+9$ as follows:

$5a-3+\lvert a+4 \rvert =4a+9$

$\lvert a+4\rvert =4a+9-5a+3$

$a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)$

$2a=8\,\,\text{or}\,\,4=12$

So, the unique solution of this last equation is $a=4$

The last equation is $h(x-1)=x-3$ , where $h(x)=\lvert x \rvert -2x+5.$ . To solve this equation we can proceed as follows:

$h(x-1)=x-3$

$\lvert x-1\rvert -2(x-1)+5=x-3$

$\lvert x-1 \rvert -2x+2+5=x-3$

$\lvert x-1\rvert =3x-10$

$x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)$

$-2x=-9\,\,\text{or}\,\,4x=11$

$x=9/2\,\,\text{or}\,\,x=11/4$

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0

3 years ago