Answer:
Step-by-step explanation:
The rate if increase of side of square is 7cm/s
dL/dt=7
At what area is the area increasing
dA/dt=?
Areas of square is give to be 36cm²
Analysis
Let L be the length of each side of the square, a square has equal side.
Area of square is give as L²
Area=L²
L²=36
i.e L=√36
L=6cm
Therefore at t=0 L=6cm and A=36cm²
A=L²
dA/dL=2L
Given that, dL/dt=7
Multiply the two differential together
dA/dt= dA/dL × dL/dt
dA/dt= 2L × 7
dA/dt= 2×6×7
dA/dt= 84cm²/s
The rate of increase of the square is 84cm²/s
Let x and y represent the two angles.
.. x + y = 90 . . . . . . two angles are complementary
.. x -2y = 15 . . . . . . one angle is 15 more than twice the other (y = smaller angle)
Subtract the second equation from the first.
.. (x +y) -(x -2y) = (90) -(15)
.. 3y = 75
.. y = 25
The smaller angle is 25 degrees.
U can change it by using the rule of logarithm.
log (10/y)= log10 - log y
Answer:
5400
Step-by-step explanation:
X+ 3y = 1 -----(first equation)
-2x+7 = -23 ---(second equation)
-2x = -23-7
x = 30/2
x = 15
Now, Substitute the value of x in first equation,
15 + 3y = 1
3y = 1 - 15
y = -14/3
In short, Final Answers are: x = 15 & y = -14/3
Hope this helps!
