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marshall27 [118]
4 years ago
7

The least common multiple of two numbers is 60 and one of the numbers is seven less than the other number what are the numbers

Mathematics
1 answer:
mihalych1998 [28]4 years ago
6 0
53 or it could be 60 multiply common multiple
You might be interested in
Cual es la ecuacion lineal de estos infinita solucion o no solucion<br>​
coldgirl [10]

Cuando has simplificado la ecuación lo mas posible y las expresiones de los dos lados quedan iguales, hay soluciones infinitas.  Pero, dado que lo has simplificado y son diferentes, no hay solución.

1.) 7x = 12 + 7x - 12

=> 7x = 7x => infinita solución

2.) x - 11 = 11 + x

=> x = 22 + x => no solución

3.) 2(4x - 6) = 8(x + 2)

=> 8x - 12 = 8x + 16 => 8x = 8x + 28 => no solución

4.) 2x - 9 = 2x - 9

=> infinita solución

5.) 8 + 4x = 4x + 10

=> 4x = 4x - 2 => no solución

6 0
3 years ago
What is the greatest common factor of 10x and 22x“?
BartSMP [9]

Answer:

2x

Step-by-step explanation:

x and 2 are common to both 10x and 22x, so 10x + 22x = 2x(5 + 11)

The GCF is 2x.

4 0
3 years ago
Plz it’s for my finals!!
Mrac [35]
Pretty sure it would be D

Good luck on your finals!
3 0
3 years ago
Describe what the notation upper p left parenthesis upper b vertical line upper a right parenthesis represents. choose the corre
morpeh [17]
The correct answer is b), the probability of B occurring given A has occurred.
8 0
4 years ago
Read 2 more answers
Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer​
Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

5 0
3 years ago
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