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Phoenix [80]
3 years ago
9

What is the GCF of 14 and 42? Thanks!

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
8 0
14 is the GCF because 42 is divisible by 14
mixas84 [53]3 years ago
5 0

Answer: 2x7.2x7

Step-by-step explanation:

So first you write down 14 then small lines going downwards divide 14 by 2 to get 7. Then write 2 and 7 below the two small lines then circle the to indicate that you got your final answer.

Write down 42 then draw two small lines underneath it, divide 42 by 2 to get 21.

The write 21 and 2 below the lines then see if you can divide 21 anymore but first circle the 2 to show your done with the 2. You can divide 21 by 3 so divide 21 by 3 to get 7 then draw a small line below 21 and write 7 then since you can’t divide 7 you circle then 7 then your done.

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leonid [27]
I believe your answer is 6 seconds.

Because the height of the ball = -16(x² - 5x - 6), when the height of the ball is 0, which is when it is on the ground, we can set -16(x² - 5x - 6) equal to 0. This also allows us to divide by -16, and then we can solve the equation:

x² - 5x - 6 = 0
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So x = 6 or x = -1, and because a quantity of time cannot be negative, x would have to be 6, which means it takes 6 seconds for the ball to reach 0 feet.

I hope this helps!
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3 years ago
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Vesna [10]

You're looking for the largest number <em>x</em> such that

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Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

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So there is no such number.

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Step-by-step explanation:

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