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4 years ago

Categorize the graph as linear increasing, linear decreasing, exponential growth, or exponential decay.

Mathematics

2 answers:

Ber [7]4 years ago

6 0

Answer:

A) linear decreasing

Step-by-step explanation:

A linear graph is a straight line. This graph is a straight line.

A decreasing graph is one in which as the x-value increases, the y-value decreases; we can see this is true of this graph.

This makes the graph a linear decreasing graph.

dusya [7]4 years ago

3 0

A. Linear Decreasing

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Step-by-step explanation:

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3 years ago

An article titled "Teen Boys Forget Whatever It Was" appeared in the Australian newspaper The Mercury (April 21, 1997). It descr

Step2247 [10]

Answer:

We conclude that the average attention span for teenage boys is less than 5 minutes.

Step-by-step explanation:

We are given that the mean time to distraction for teenage boys working on an independent task was 4 minutes.

Suppose that this mean was based on a random sample of 50 teenage Australian boys and that the sample standard deviation was 1.4 minutes.

Let $\mu$ = average attention span for teenage boys

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 5 minutes {means that the average attention span for teenage boys is more than or equal to 5 minutes}

Alternate Hypothesis, $H_A$ : $\mu$ < 5 minutes {means that the average attention span for teenage boys is less than 5 minutes}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean attention time span for teenage boys = 4 min

s = sample standard deviation = 1.4 min

n = sample of teenage boys = 50

So, the test statistics = $\frac{4-5}{\frac{1.4}{\sqrt{50} } }$ ~ $t_4_9$

= -5.051

Now at 0.01 significance level, the t table gives critical value of -2.405 at 49 degree of freedom for left-tailed test. Since our test statistics is less than the critical value of t as -2.405 > -5.051, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average attention span for teenage boys is less than 5 minutes.

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4 years ago

An insurance salesman sells on average 10.4 life insurance policies per week. Find the probability that in a particular week he

Fittoniya [83]

Answer:

$P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}, X= 0,1,2,...$

$P(X=8) = \frac{e^{-10.4} 10.4^8}{8!}= 0.1033$

And that would be the solution for this case.

Step-by-step explanation:

Previous concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

$P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}, X= 0,1,2,...$

Solution to the problem

Let X the random variable that represent the number of life insurance policies that the salesman person sells. We know that $X \sim Poisson(\lambda=10.4)$