Answer:
b^2 + 4 a b - 2 b - 2 a^2 + -5 a
Step-by-step explanation:
Simplify the following:
-2 a (a + b - 5) + 3 (2 b - 5 a) + b (6 a + b - 8)
-2 a (-5 + a + b) = 10 a - 2 a^2 - 2 a b:
10 a - 2 a^2 - 2 a b + 3 (2 b - 5 a) + b (6 a + b - 8)
3 (2 b - 5 a) = 6 b - 15 a:
10 a - 2 a^2 - 2 a b + 6 b - 15 a + b (6 a + b - 8)
b (-8 + 6 a + b) = -8 b + 6 a b + b^2:
10 a - 2 a^2 - 2 a b - 15 a + 6 b + -8 b + 6 a b + b^2
Grouping like terms, 10 a - 2 a^2 - 2 a b - 15 a + 6 b - 8 b + 6 a b + b^2 = b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a):
b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)
a b 6 + a b (-2) = 4 a b:
b^2 + 4 a b + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)
6 b - 8 b = -2 b:
b^2 + 4 a b + -2 b - 2 a^2 + (10 a - 15 a)
10 a - 15 a = -5 a:
Answer: b^2 + 4 a b - 2 b - 2 a^2 + -5 a
Isn't there no resistance between a light bulb that uses 15 watts of power when it is placed across a 15-volt battery?
Answer:
37
Step-by-step explanation:
all triangle's angle measures add up to 180
180-98-45 = x
x = 37
Answer:
A) 4.77%.
B) 5%.
Step-by-step explanation:
Given that Adam borrows $ 6,000 from his parents today for university fees and he promises to pay a lump sum of $ 6,900 in 3 years' time, to calculate the effective annual interest rate and the equivalent simple annual interest rate the following calculations must be performed:
A)
6,900 = 6,000 x (1 + X / 1) ^ 3x1
6,900 = 6,000 x 1X ^ 3
6,900 = 6,000 x 1 x 4.77 ^ 3
Thus, the interest rate of said investment is 4.77% per year.
B)
(6,900 - 6,000) / 3 = 300
6,000 = 100
300 = X
300 x 100 / 6,000 = X
30000 / 6,000 = X
5 = X
Thus, the simple interest rate would be 5% per year.
Answer:
The 1st and 4th statements are true.