A 1.50 liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25oC. Without change in t
emperature, a piston is moved in the cylinder until the pressure in the cylinder is reduced to 1.00 atmosphere. The volume of the gas is:
2 answers:
At constant temperature, volume and pressure of a gas may be considered inversely proportional. This is pV = constant.
Then, 3.00 atm * 1.5 liter = 1atm*V
Solve for V, to obtain V = 3atm*1.5liter / 1atm = 4.5 liter
Answer: 4.5 liter
The answer is 4.5 l
To calculate this, we will use the Boyle's law using constant k, pressure P, and volume V:
PV = k
We can forget temperature since it is constant.
We have:
P1V1 = k
P2V2 = k
So, P1V1 = P2V2
P1 = 3 atm
V1 = 1.5 l
P2 = 1 atm
V2 = ?
_____
P1V1 = P2V2
3 atm * 1.5 l = 1 atm * V2
4.5 atm/l = 1 atm * V2
V2 = 4.5 atm l / 1 atm
V2 = 4.5 l
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