Question

Find the value of y...​

Answer 1

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

3$3^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1$

Calculate:

$(3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1$

Solve using substitution:

$(3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1$     $t=3^{y}$

Solve the equation for t:

$t^{2}*\frac{1}{3}+\frac{2}{3}t=1$

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

$3^{y}=1$

y=0