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Dmitry [639]
4 years ago
7

11. A city phone book has 86 pages filled with residents' names. There are

Mathematics
1 answer:
NNADVOKAT [17]4 years ago
4 0
Jeiocyppgcrtkttksksiitisttsosotststostststststosyodotdoydtodoydyodyodoydoydoysoydotdotdyodyod
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Sketch the graph of each rational function showing all the key features. Verify your graph by graphing the function on
leva [86]

Answer:

Rational Function

Step-by-step explanation:

Gives the function:

f(x) = \frac{x-2}{3x-2x^2}

It has the following,

Domain

x∈ \mathbb{R} : x\neq 0, x\neq 3/2

Range

f \in \mathbb{R} : f \leq -1, f \geq -\frac{1}{9}

End behaviour

As xx \rightarrow \infty, y \rightarrow 0

Horizontal and Vertical Asymptote

Vertical x = 0, x=3/2

Horizontal y = 0

<em>x-intercept: (2,0)</em>

<em>y-intercept: none</em>

<em>**The Graph is in the annex</em>

5 0
3 years ago
Please solve it ASAP 50 points
TiliK225 [7]

Answer:

?

.

Step-by-step explanation:

4 0
3 years ago
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I can’t seem to find this, I’m having trouble with this question! It would be nice if someone could help! Thanks
Elenna [48]

Answer:

-456 I think but I could be wrong though

8 0
2 years ago
HELP PLEASE!!
shutvik [7]

Answer:

6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.

:}

8 0
3 years ago
Read 2 more answers
The mayor of a town believes that over 47G% of the residents favor construction of an adjoining community. Is there sufficient e
photoshop1234 [79]

Answer:

There is sufficient evidence at the 0.05 level

Null hypothesis ; H0 : p = 0.47

Alternative hypothesis : H1 : p ≠ 0.47

Step-by-step explanation:

percentage favoring construction of adjoining community = 47%

level = 0.05

To determine if the 0.05 confidence level is enough to support the major's claim we have to state the Null and alternative hypothesis

Null hypothesis ; H0 : p = 0.47

Alternative hypothesis : H1 : p ≠ 0.47

5 0
3 years ago
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