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ASHA 777 [7]
3 years ago
9

The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Mathematics
2 answers:
Vesna [10]3 years ago
8 0
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\
\boxed{(x-4)^2+y^2=12}
Ierofanga [76]3 years ago
4 0

The equation of such a circle, described as
set forth in the question, is

                                         (x-4)² + y² = 12        .


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A blimp is 1600 meters high in the air and measures the angles of depression to two stadiums to the east of the blimp. if those
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The two stadiums are 2,871 meters

A blimp    = point A

stadium 1  = point B

stadium 2 = point C

height of the blimp ,  AD = 1600

depression angle of stadium 1 , ∠y = 71.7°

depression angle of stadium 2 , ∠x = 25.2°

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So, it forms 2 triangles  ABD and ACD,

Using the trigonometric ratios,

tan θ = Altitude / Base

DC = AD × tan (90° - x)

= 1600 × tan( 90° - 25.2° )

= 1600 × cot(25.2°)

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DB = AD × tan (90° - y)

= 1600 × tan( 90° - 71.7° )

= 1600 × cot(71.7°)

= 1600 × 0.33

∴ d = DC - DB

     = 1600 * [ tan( 90° - 25.2° ) - tan( 90° - 71.7° ) ]

    = 2,871 meters

To learn more about angle of depression from the given link

brainly.com/question/9723082

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Step-by-step explanation:

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Vanyuwa [196]

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Step-by-step explanation:

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