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ASHA 777 [7]
3 years ago
9

The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Mathematics
2 answers:
Vesna [10]3 years ago
8 0
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\
\boxed{(x-4)^2+y^2=12}
Ierofanga [76]3 years ago
4 0

The equation of such a circle, described as
set forth in the question, is

                                         (x-4)² + y² = 12        .


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