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nataly862011 [7]
4 years ago
15

H(x) = 3x - 4 What is h(6)? ETĀ. 14 e c. 22 SUBMIT

Mathematics
2 answers:
AleksandrR [38]4 years ago
6 0

Answer:

a. 14 is your answer.

Step-by-step explanation:

h(x) = 3x - 4

h(6) = ?

Plug in 6 for x: x = 6

h(6) = 3(6) - 4

Remember to follow PEMDAS. First, multiply, then subtract:

h(6) = (3 * 6) - 4

h(6) = (18) - 4

Simplify:

h(6) = 18 - 4

h(6) = 14

a. 14 is your answer.

~

Mrac [35]4 years ago
4 0

h(6)=3\cdot6-4=14

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Answer:

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Step-by-step explanation:

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AC = <br> Round your answer to the nearest hundredth.
dusya [7]

Answer:

AC ≈ 5.03

Step-by-step explanation:

We can solve the problem above using the trigonometric ratio, they are;

SOH CAH TOA

sin Ф = opposite / hypotenuse

cosФ= adjacent/ hypotenuse

tan Ф = opposite / adjacent

From the diagram above, in reference to angle B;

opposite =AC     and   adjacent =BC

Since we have opposite and adjacent, the best formula to use is

tanФ = opposite / adjacent

tan B = AC  / BC

tan 40 =  AC/ 6

Multiply both-side of the equation by 6

6× tan 40   =  AC/ 6  ×  6

At the right-hand side of the equation, 6 will cancel-out 6 leaving us with just AC

6×tan 40 = AC

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4 0
3 years ago
How do I solve it. I don't understand where I should start the problem I have the formulas
Luda [366]
V=length times width times height
wait, we need it in yards
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4 years ago
Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −
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Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

(x-h)^2+(y-k)^2=r^2

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

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Lets arrange the third equation, in standard form of equation of circle as,

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The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

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