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2 years ago

What is the dot product of u = (11, 4, -2) and v = (-1, 3, 8)

Mathematics

1 answer:

NARA [144]2 years ago

4 0

11.-1+4.3+-2.8
-11+12-16
-15
I think

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What is y+4=9 what is y?

amid [387]

Answer:

$y = 5$

Step-by-step explanation:

Subtract the 4 from 9

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3 years ago

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A ball is dropped from a height of 14 ft. The elasticity of the ball is such that it always bounces up one-third the distance it

Korvikt [17]

Answer:

Hello,

742/27 (ft)

Step-by-step explanation:

$h_1=14\\\\h_2=\dfrac{14}{3} \\\\h_3=\dfrac{14}{9} \\\\h_4=\dfrac{14}{27} \\\\$

$d=14+2*\dfrac{14}{3} +2*\dfrac{14}{9} +2*\dfrac{14}{27} \\=14*(1+\dfrac{1}{3}+\dfrac{2}{9} +\dfrac{2}{27} )\\=14*\dfrac{53}{27} \\=\dfrac{742}{27} \\$

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2 years ago

Please help ! This is 7th grade math and I’ve been stuck on this question for 30 minutes!

FinnZ [79.3K]

$\dfrac{1}{22}\:\dfrac{\text{in}}{\text{hr}}$

Step-by-step explanation:

The amount of time from 10pm to 7am is 9 hours. However, the time indicated is 7:10am. Since there are 60 minutes in an hour, 10 min is equal to 1/6 of an hour. Therefore, the total time that the water level of the pool decreased is $9\frac{1}{6}$ hours or $\frac{55}{6}$ hours. To find the rate at which the water level decreased, we divide the change in the water (in inches) by the time it took to reach that level. So we write

rate of change $= \dfrac{\text{change\:in\:height}}{\text{change\:in\:time}}$

$\:\:\:\:\:\:\:= \dfrac{\frac{5}{12}\:\text{in}}{\frac{55}{6}\:\text{hrs}}$

$\:\:\:\:\:\:\:=\dfrac{5}{12}\cdot\dfrac{6}{55}\:\dfrac{\text{in}}{\text{hr}}$

$\:\:\:\:\:\:\:= \frac{1}{22}\:\dfrac{\text{in}}{\text{hr}}$

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2 years ago

(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app

Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

b) P(B) = P(A1B)+P(A2B)

Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads. $P(B/A1) = 0.50 \\P(B/A2) = 0.75\\P(A1B) = 0.5(0.5) = 0.25 \\P(A2B) = 0.75(0.5) = 0.375\\P(B) = 0.625$