Keeping in mind that for a cost C(x) and profit P(x) and revenue R(x), the marginal cost, marginal profit and marginal revenue are respectively dC/dx, dP/dx and dR/dx, then
![\bf P(x)=0.03x^2-3x+3x^{0.8}-4400 \\\\\\ \stackrel{marginal~profit}{\cfrac{dP}{dx}}=0.06x-3+2.4x^{-0.2} \\\\\\ \cfrac{dP}{dx}=0.06x-3+2.4\cdot \cfrac{1}{x^{0.2}}\implies \cfrac{dP}{dx}=0.06x-3+2.4\cdot \cfrac{1}{x^{\frac{1}{5}}} \\\\\\ \cfrac{dP}{dx}=0.06x-3+\cfrac{2.4}{\sqrt[5]{x}}](https://tex.z-dn.net/?f=%5Cbf%20P%28x%29%3D0.03x%5E2-3x%2B3x%5E%7B0.8%7D-4400%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7Bmarginal~profit%7D%7B%5Ccfrac%7BdP%7D%7Bdx%7D%7D%3D0.06x-3%2B2.4x%5E%7B-0.2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7BdP%7D%7Bdx%7D%3D0.06x-3%2B2.4%5Ccdot%20%5Ccfrac%7B1%7D%7Bx%5E%7B0.2%7D%7D%5Cimplies%20%5Ccfrac%7BdP%7D%7Bdx%7D%3D0.06x-3%2B2.4%5Ccdot%20%5Ccfrac%7B1%7D%7Bx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7BdP%7D%7Bdx%7D%3D0.06x-3%2B%5Ccfrac%7B2.4%7D%7B%5Csqrt%5B5%5D%7Bx%7D%7D)
Answer:
148.005
Step-by-step explanation:
Answer:
(C)18 units
Step-by-step explanation:
- Point G is the centroid of triangle ABC.
- C is a vertex of the triangle
- D is the midpoint of the side opposite the vertex.
From Centroid Theorems, we know that the distance from the centroid to the vertex is twice as long as the distance from the centroid to the midpoint of the side opposite the vertex.
Therefore:
CG=2DG
Let the length of segment DG =x
The length of segment CG is 6 units greater, therefore: CG=x+6
Substituting into CG=2DG:
x+6=2x
2x-x=6
x=6 Units
Therefore:
CD=CG+GD
=6+6+6
=18 Units
<u><em>The correct option is C.</em></u>
16*15 =240
240*s where s = number of students in Mr McDonalds class
Answer:
b. 9/50
Step-by-step explanation:
•the probability of the selected flight arriving on time: 820/1000 = 0.82
•find the probability of the flights not being selected by subtracting 0.82 from 1.00: 1.00-0.82=0.18
•now you look for the answer that equals to 0.18
50/1 =50 nope
9/50 =0.18 yes
41/50 =0.82 nope
1/4 = 0.25 nope