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alexira [117]
3 years ago
6

On a scale drawing a school is 1.6 feet tall the scale factor is 1/22 find the height of the school

Mathematics
1 answer:
vodomira [7]3 years ago
5 0

I believe the school is 35.2 ft. tall. call me out if I'm wrong.

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Flora has 33 flowers and she can pick 7 flowers a minute. Write an equation that shows how many flowers, F, that Flora will have
monitta
F=7M
33=M
Both answers will work
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Thang decided to borrow ​$7000 from his local bank to help pay for a car. His loan was for 3 years at a simple interest rate of
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What is the perimeter of this square?
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We need the square and the lengths of it to help you
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3 years ago
Two runners start at the same point;Jayne and Jared.
Tomtit [17]

Answer:

160

Step-by-step explanation:

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6 0
2 years ago
Write the polynomial in factored form as a product of linear factors f(r)=r^3-9r^2+17r-9
adelina 88 [10]

Answer:

  f(r) = (x -1)(x -4+√7)(x -4-√7)

Step-by-step explanation:

The signs of the terms are + - + -. There are 3 changes in sign, so Descartes' rule of signs tells you there are 3 or 1 positive real roots.

The rational roots, if any, will be factors of 9, the constant term. The sum of coefficients is 1 -9 +17 -9 = 0, so you know that r=1 is one solution to f(r) = 0. That means (r -1) is a factor of the function.

Using polynomial long division, synthetic division (2nd attachment), or other means, you can find the remaining quadratic factor to be r^2 -8r +9. The roots of this can be found by various means, including completing the square:

  r^2 -8r +9 = (r^2 -8r +16) +9 -16 = (r -4)^2 -7

This is zero when ...

  (r -4)^2 = 7

  r -4 = ±√7

  r = 4±√7

Now, we know the zeros are {1, 4+√7, 4-√7), so we can write the linear factorization as ...

  f(r) = (r -1)(r -4 -√7)(r -4 +√7)

_____

<em>Comment on the graph</em>

I like to find the roots of higher-degree polynomials using a graphing calculator. The red curve is the cubic. Its only rational root is r=1. By dividing the function by the known factor, we have a quadratic. The graphing calculator shows its vertex, so we know immediately what the vertex form of the quadratic factor is. The linear factors are easily found from that, as we show above. (This is the "other means" we used to find the quadratic roots.)

7 0
3 years ago
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