It has been proven that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
<h3>How to prove a Line Segment?</h3>
We know that in a triangle if one angle is 90 degrees, then the other angles have to be acute.
Let us take a line l and from point P as shown in the attached file, that is, not on line l, draw two line segments PN and PM. Let PN be perpendicular to line l and PM is drawn at some other angle.
In ΔPNM, ∠N = 90°
∠P + ∠N + ∠M = 180° (Angle sum property of a triangle)
∠P + ∠M = 90°
Clearly, ∠M is an acute angle.
Thus; ∠M < ∠N
PN < PM (The side opposite to the smaller angle is smaller)
Similarly, by drawing different line segments from P to l, it can be proved that PN is smaller in comparison to all of them. Therefore, it can be observed that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
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Solution is supposed to be as follows
<span>u+<span>2 / 3</span><span> u<span>^3/2</span></span>
=r+<span>2 / 3</span><span> r^<span>3/2</span></span> + <span>c</span></span>
Answer:
2 was not multiplied by 5
Step-by-step explanation:
2(x + 5) = 2x + 5
The correct expansion form distributive property should be :
2(x + 5) = 2*x + 2*5 = 2x + 10
2(x + 5) = 2x + 10
Answer:
3.14
Step-by-step explanation:
because its diameter that is 2, you divide it in half which should be one, that will be the radius. to get the area from the radius you multiply it by its self and multiply that by 3.14 which is the circumference of a circle.
Twenty-four is the total.
So 14/24 would be the probability of a student who got an A to be chosen.
Fraction: 7/12
Percentage: 58.3%
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