Answer: It is a Double Displacement(Replacement) Reaction.
Explanation:
The standard of something as measured against other things of a similar kind; the degree of excellence of something
Balancing of the chemical reaction involves keeping the number of atoms of a certain element equal in both sides of the equation. For this item, the balanced chemical equation would be,
N2 + 3H2 --> 2NH3
The numerical coefficients are therefore 1 for N2, 3 for H2, and 2 for NH3. The sum of the numerical coefficients is 6.
<em>Answer: 6</em>
Answer:
C. It has the same types of atoms on both sides of the reaction arrow.
<h2>What is a chemical equation?</h2>
A chemical equation is a symbolic representation of a chemical reaction; Reactants are represented on the left and the products on the right.
The law of conservation of mass states that in a closed system, mass is neither created nor destroyed during a chemical or physical reaction. The law of conservation of mass is applied whenever you balance a chemical equation. It is also applicable to stoichiometry. A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow.
Consider the balanced equation for the combustion of methane.
![CH_4 + 20_2 \implies CO_2 + 2H_2O](https://tex.z-dn.net/?f=CH_4%20%2B%2020_2%20%5Cimplies%20CO_2%20%2B%202H_2O)
All balanced chemical equations must have the same number of each type of atom on both sides of the arrow.
In this equation, we have 1 C atom, 4 H atoms, and 4 O atoms on each side of the arrow.
The number of atoms does not change, so the total mass of all the atoms is the same before and after the reaction. Mass is conserved.
The same atoms of the same element that are present in the reactants are also present in the products, according to the rule of conservation of matter.
This leads us to believe that the response to the question is true because: It has the same atom kinds on both sides of the reaction arrow (Option C)
#SPJ2
Answer:
The final vapor pressure is 687.24mmHg
Explanation:
The clausius-clapeyron equation below will be used to solve this problem:
![ln\frac{P_2}{P_1} =\frac{\delta H}{R}(\frac{1}{T_1}-\frac{1}{T_2})](https://tex.z-dn.net/?f=ln%5Cfrac%7BP_2%7D%7BP_1%7D%20%20%3D%5Cfrac%7B%5Cdelta%20H%7D%7BR%7D%28%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%29)
Where;
ΔH is heat of vaporization = 450 kJ/mol = 450000J/mol
initial vapor pressure P₁ = 400mmHg
initial temperature T₁ = 3030K
Final temperature T₂ = 3070K
R is ideal gas constant = 8.314 J/molK
final vapor pressure P₂ = ?
![ln\frac{P_2}{400} =\frac{450000}{8.314}(\frac{1}{3030}-\frac{1}{3070})](https://tex.z-dn.net/?f=ln%5Cfrac%7BP_2%7D%7B400%7D%20%20%3D%5Cfrac%7B450000%7D%7B8.314%7D%28%5Cfrac%7B1%7D%7B3030%7D-%5Cfrac%7B1%7D%7B3070%7D%29)
![ln\frac{P_2}{400} =(54125.57)(0.00001)](https://tex.z-dn.net/?f=ln%5Cfrac%7BP_2%7D%7B400%7D%20%20%3D%2854125.57%29%280.00001%29)
![ln\frac{P_2}{400} =(0.5412557)](https://tex.z-dn.net/?f=ln%5Cfrac%7BP_2%7D%7B400%7D%20%20%3D%280.5412557%29)
![\frac{P_2}{400} = e^{(0.5412557)}](https://tex.z-dn.net/?f=%5Cfrac%7BP_2%7D%7B400%7D%20%3D%20e%5E%7B%280.5412557%29%7D)
P₂/400 = 1.7181
P₂ = (400*1.7181)mmHg
P₂ = 687.24mmHg
The final vapor pressure is 687.24mmHg