the latest weather report includes the following statement: the temperature is 78°f, barometric pressure is 29 and the relative
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<u>Answer:</u> The percent yield of the reaction is 32.34 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For benzoic acid:</u>
Given mass of benzoic acid = 3.6 g
Molar mass of benzoic acid = 122.12 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of benzoic acid and methanol is:
By Stoichiometry of the reaction
1 mole of benzoic acid produces 1 mole of methyl benzoate
So, 0.0295 moles of benzoic acid will produce = moles of methyl benzoate
- Now, calculating the mass of methyl benzoate from equation 1, we get:
Molar mass of methyl benzoate = 136.15 g/mol
Moles of methyl benzoate = 0.0295 moles
Putting values in equation 1, we get:
- To calculate the percentage yield of methyl benzoate, we use the equation:
Experimental yield of methyl benzoate = 1.3 g
Theoretical yield of methyl benzoate = 4.02 g
Putting values in above equation, we get:
Hence, the percent yield of the reaction is 32.34 %
Answer : The value of of the gas is 2.79 Joules.
Explanation :
First we have to calculate the moles of helium.
Molar mass of helium = 4 g/mole
Now we have to calculate the heat.
Formula used :
where,
q = heat
n = number of moles of helium gas = 0.0125 mole
= specific heat of helium = 20.8 J/mol.K
= initial temperature = 310.0 K
= final temperature = 235.0 K
Now put all the given values in the above formula, we get:
Now we have top calculate the work done.
Formula used :
where,
w = work done
p = pressure of the gas = 1 atm
= initial volume = 1.21 L
= final volume = 0.99 L
Now put all the given values in the above formula, we get:
conversion used : (1 L.atm = 101.3 J)
Now we have to calculate the value of of the gas.
Therefore, the value of of the gas is 2.79 Joules.