Question

According to the following reaction, how many moles of iron(III) chloride will be formed upon the complete reaction of 26.2 grams of iron with excess chlorine gas ?
iron(s) + chlorine(g) iron(III) chloride(s)

Answer 1

Answer:

0.469 mol FeCl₃

Explanation:

Your reaction as a chemical equation is:

2 Fe (s)  +  3 Cl₂ (g)  ⇒  2 FeCl₃ (s)

You have 26.2 grams of iron.  Convert to moles of iron.

(26.2 g)/(55.845 g/mol) = 0.4692 mol

Use the mole ratio from the chemical equation to convert moles of iron to moles of iron(III) chloride.

(0.4692 mol Fe) × (2 mol FeCl₃/2 mol Fe) = 0.469 mol FeCl₃

You will have 0.469 moles of iron(III) chloride at the end of the reaction.