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weqwewe [10]
3 years ago
10

First set of offspring in an experiment​

Biology
1 answer:
SSSSS [86.1K]3 years ago
8 0

Answer:

F1

Explanation:

These offspring were called the F 1, or the first filial (filial = offspring, daughter or son), generation. Once Mendel examined the characteristics in the F1 generation of plants, he allowed them to self-fertilize naturally.

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Will someone comment they cashapp after they answer these questions.
Rufina [12.5K]

Answer:

Detail is given below.

Explanation:

Given data:

Mass of enzyme = 32 g

Volume of water = 42.50 mL

Volume of water+ enzyme = 48.0 mL

Density of enzyme = ?

Solution:

Density is equal to the mass divided by volume.

First of all we will calculate the volume of enzyme.

Volume of enzyme = (volume of water+ enzyme ) - Volume of water

Volume of enzyme = 48.0 mL - 42.50 mL

Volume of enzyme =  5.5 mL

Density of enzyme:

d = 32 g/  5.5 mL

d = 5.8 g/mL

2)

Given data:

Mass of cup = 14 g

Volume of cup = ?

Density of cup = 2 g/cm³

Solution:

Density is equal to the mass divided by volume.

Formula:

d = m/v

2 g/cm³  = 14 g/  v

v = 14 g/2 g/cm³

v = 7 cm³

3) What are the four ways to measure matter?

weight, mass, volume, density

4) Given data:

Mass of rock = 18.5 g

volume of rock = 3cm³

density of rock = ?

Solution:

Formula:

d = m/v

d  = 18.5 g/ 3cm³

v = 6.16 g/cm³

5)

Given data:

mass = 6g

density = 8 g/cm³

missing value = ?

Solution:

d = m/v

8 g/cm³ = 6g / v

v = 6g/8 g/cm³

v = 0.75cm³

6)

Given data:

Volume of liquid in cylinder = 48 mL

Volume of toy car and liquid = 52 mL

Volume of car = ?

Solution:

Volume of car = volume of of toy car and liquid - Volume of liquid in cylinder

Now we will put the values.

Volume of car = 52 mL - 48 mL

Volume of car = 4 mL

7 0
3 years ago
Arrange the following list of eukaryotic gene elements in the order they would appear in the genome and in the direction travele
Leni [432]

Answer:

The alignment of the elements in the following sequence will take place in the eukaryotic genome:  

a. Promoter

b. Nucleotide to which methylated cap is added

c. 5 prime UTR

d. Initiation codon

e. Splice donor

f. Splice branch site

g. Splice acceptor

h. Stop codon

i. 3 prime UTR

j. Transcription terminator

k. Poly A addition site

After the process of splicing, the ultimate transcript will comprise the elements b, c, d, h, i. In eukaryotes, the RNA polymerase begins the process of transcription after it crosses the promoter region, and ceases at the transcription terminator. At the time of RNA processing, a 5 prime cap is supplemented to the transcript, splicing occurs, and a poly-A tail is supplemented. The 5 prime UTR and 3 prime UTR regions are found in the final transcript, that is, the mature RNA, however, are not translated.  

4 0
4 years ago
When a honeybee pollinates a flower, the symbiosis would be _______
Sedaia [141]

Answer:

The relationship between them is mutualism because both organisms benefit.

Explanation:

The honey bee gains nectar from the plant while the flower is pollinated.

PLEASE MARK AS BRAINLIEST.

8 0
3 years ago
Which of the two types of cells, xylem or phloem, has the largest diameter
Ratling [72]

Answer:

Which of the two types of cells, xylem or phloem, has the largest diameter

XYLEM

Explanation:

Reason being that xylem has a larger conducting vessels which helps in the aggregation of its sapwood unlike phloem which has a lower conductivity area

7 0
3 years ago
How can atoms in sugar molecules be used to form amino acids and other large carbon base molecules?
nika2105 [10]

Answer:

The sugar molecules thus formed contain carbon, hydrogen, and oxygen: Their hydrocarbon backbones are wont to make amino acids and other carbon-based molecules which will be assembled into larger molecules (such as proteins or DNA), used for instance to make new cells.

Explanation:

6 0
3 years ago
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