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givi [52]
3 years ago
14

What term describes 3y-5

Mathematics
1 answer:
Arisa [49]3 years ago
4 0
Please provide more information.
You might be interested in
Step 1: 4y − 2y − 4 = −1 + 13
d1i1m1o1n [39]
You didn't list the options
btw
the next step should be

(add 4 to both sides)
2y = 16
or
2y - 4 + 4 = 12 + 4 
8 0
3 years ago
Find the product. a 4 (3 a 2 - 2 a + 1)
Basile [38]
a^4(3a^2-2a+1) = 3a^6-2a^6+a^4 because of the distributive property and exponent laws. 
8 0
4 years ago
A rectangular lawn is 65 m long and 34 m wide. Over time, people have walked along a diagonal as a shortcut and have created a s
irina [24]
To calculate the length of the diagonal, use the Pythagorean theorem:
c^2 = a^2 + b^2, where c is the diagonal.
c^2 = 65^2 + 34^2
c^2 = 4225 + 1156
c^2 = 5381
c ~ 73.36
To the nearest tenth of a meter, the diagonal has a length of 73.4 m
3 0
3 years ago
Read 2 more answers
Daniela needs to cut a rectangular hole in a wall where a new window will be installed. The window will be 4 feet high and 3 fee
BlackZzzverrR [31]

Answer:

Measure the diagonals, they should be 5 feet (3,4,5 triangle).

Step-by-step explanation:

As a more general answer, the diagonal measurements of ANY rectangle will be equal. You can calculate the correct measurement using A^2 + B^2 = C^2. A and B are the lengths of the sides and C is the length of the diagonals.

8 0
3 years ago
A company manufactures light bulbs. The lifetime for these bulbs is 4,000 hours with a standard deviation of 200 hrs. What lifet
arlik [135]

Answer:

The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 4000, \sigma = 200

What lifetime should the company promote for these bulbs, whereby only 2% burnout before the claimed lifetime?

This is the value of X when Z has a pvalue of 0.02. So it is X when Z = -2.055.

Z = \frac{X - \mu}{\sigma}

-2.055 = \frac{X - 4000}{200}

X - 4000 = -2.055*200

X = 3589

The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime

4 0
3 years ago
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