Answer:
The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.
Step-by-step explanation:
When we do not know the shape of the distribution, we use the Chebyshev's Theorem to find the minimum percentage of a measure within k standard deviations of the mean.
This percentage is:

Within 8 standard deviations of the mean
This means that
. So

The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.
Answer:
Step-by-step explanation:
a) (a + b)² = (a + b) * (a +b)
(a + b)³ = (a + b) * (a +b) * (a +b)
a²- b² = (a +b) (a - b)
Here (a + b) is common in all the three expressions
HCF = (a + b)
b) (x - 1) = (x - 1)
x² - 1 = (x - 1) * (x + 1)
(x³ - 1) = (x - 1) (x² + x + 1)
HCF = (x -1)
200:22, 400:44, so there are 6 more marked deers left. To find them, 200/22, 9.09090909....., so 9.09090909*50 = 454.54545454 (round that and you get 455, hence the answer would be C).