Please help! Prove: Ray E B bisects ∠AEC.
2 answers:
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Answer:
See Below.
Step-by-step explanation:
We are given the function:
And we want to show that it has at least one zero between <em>x</em> = 1 and <em>x</em> = 2.
Because the function is a polynomial, it is everywhere continuous.
Evaluate the function at <em>x</em> = 1 and <em>x</em> = 2:
And:
Therefore, because the function changes signs from <em>x</em> = 1 to <em>x</em> = 2 and is continuous on the interval [1, 2], by the intermediate value theorem, there must exist at least one zero in the interval.