Answer:
y=3x-1
Step-by-step explanation:
X=

Or it would be approximately: x≈ 0.37228132, -5.37228132
Hope this helped! ;P
Answer:
A.
Step-by-step explanation:
yan na yannnnnnnnnnnnnnnn
Answer:
x=3
Step-by-step explanation:
8x - 12 = 4x add 12 to both sides you get 8x=4x+12 subtract 4x on both sides then you get 4x=12 divide 4x on both sides and x = 3 Hope helps!!
8x-12=4x
+12 +12
__________
8x=4x+12
-4x -4x
_______-
4x=12
÷4 ÷4
______
x=3
Hope helps :3
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.