Answer:
16x5+6x4
Step-by-step explanation:
(2x(3+5)+6)(x4)
=(2x(3+5)+6)(x4)
=(2x(3+5))(x4)+(6)(x4)
=16x5+6x4
Answer:
x = 5, y = 4
Step-by-step explanation:
![\left\{\begin{array}{ccc}4x+5y=40\\x-y=1\end{array}\right\\\\A=\left[\begin{array}{ccc}4&5\\1&-1\end{array}\right]\\\\detA=\left|\begin{array}{ccc}4&5\\1&-1\end{array}\right|=(4)(-1)-(1)(5)=-4-5=-9\\\\A^D=\left[\begin{array}{ccc}-1&-1\\-5&4\end{array}\right]\\\\\left(A^D\right)^T=\left[\begin{array}{ccc}-1&-5\\-1&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D4x%2B5y%3D40%5C%5Cx-y%3D1%5Cend%7Barray%7D%5Cright%5C%5C%5C%5CA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%265%5C%5C1%26-1%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CdetA%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D4%265%5C%5C1%26-1%5Cend%7Barray%7D%5Cright%7C%3D%284%29%28-1%29-%281%29%285%29%3D-4-5%3D-9%5C%5C%5C%5CA%5ED%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-1%5C%5C-5%264%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5Cleft%28A%5ED%5Cright%29%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-5%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D)
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![A\cdot\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}40\\1\end{array}\right] \\\\A^{-1}A\cdot\left[\begin{array}{ccc}x\\y\end{array}\right] =A^{-1}\cdot\left[\begin{array}{ccc}40\\1\end{array}\right] \\\\\left[\begin{array}{ccc}x\\y\end{array}\right] =A^{-1}\cdot\left[\begin{array}{ccc}40\\1\end{array}\right]](https://tex.z-dn.net/?f=A%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D40%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CA%5E%7B-1%7DA%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3DA%5E%7B-1%7D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D40%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3DA%5E%7B-1%7D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D40%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}\dfrac{1}{9}&\dfrac{5}{9}\\\dfrac{1}{9}&-\dfrac{4}{9}\end{array}\right]\cdot\left[\begin{array}{ccc}40\\1\end{array}\right] \\\\\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}\left(\frac{1}{9}\right)(40)+\left(\frac{5}{9}\right)(1)\\\\\left(\frac{1}{9}\right)(40)+\left(-\frac{4}{9}\right)(1)\end{array}\right]\\\\\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}5\\4\end{array}\right]\Rightarrow x=5,\ y=4](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cdfrac%7B1%7D%7B9%7D%26%5Cdfrac%7B5%7D%7B9%7D%5C%5C%5Cdfrac%7B1%7D%7B9%7D%26-%5Cdfrac%7B4%7D%7B9%7D%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D40%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cleft%28%5Cfrac%7B1%7D%7B9%7D%5Cright%29%2840%29%2B%5Cleft%28%5Cfrac%7B5%7D%7B9%7D%5Cright%29%281%29%5C%5C%5C%5C%5Cleft%28%5Cfrac%7B1%7D%7B9%7D%5Cright%29%2840%29%2B%5Cleft%28-%5Cfrac%7B4%7D%7B9%7D%5Cright%29%281%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C4%5Cend%7Barray%7D%5Cright%5D%5CRightarrow%20x%3D5%2C%5C%20y%3D4)
Answer:2
Step-by-step explanation:..
Hello,
Answer A
s(x)=3x-7
s(2t-4)=3*(2t-4)-7=6t-12-7=6t-19
Based on the dimensions of the basketball court, we can calculate that the area of the scaled copy is<u> 18 ²³/₆₄ feet².</u>
<h3>Dimensions of scaled copy</h3>
Every 16 feet of the actual court is 1 foot on the scaled copy. The dimensions of the scaled copy are therefore:
= 94 / 16 = 50 / 16
= 5.875 feet = 3.125 feet
<h3>Area of scaled copy </h3>
= Length x Width
= 5.875 x 3.125
= 18.359375
= 18 ²³/₆₄ feet²
In conclusion, the area is 18 ²³/₆₄ feet².
Find out more on area at brainly.com/question/25292087.
