Find the value of y

Mathematics

1 answer:

Rufina [12.5K]3 years ago

8 0

Answer:

y=3/2

Step-by-step explanation:

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Decide whether you would use a permutation, a combination, or neither. Next, write the solution using permutation notation or co

Zepler [3.9K]

Answer:

Permutation is used.

No. of arrangements = 1260

Step-by-step explanation:

Permutation is used for choosing & arrangement of 'r' out of 'n' objects, when sequence is important.

Total no. of alphabets in CORRECT = 7

C is repeated twice, R is repeated twice

So, Total No. of arrangements = <u>7 !</u>

(2!)(2!)

= 5040 / 4

= 1260

5 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$