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Sladkaya [172]
3 years ago
13

Need geometry help asap! image above✨

Mathematics
1 answer:
horsena [70]3 years ago
4 0
Hope this helps with the answer to your question

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Express x in terms of the other variables in the diagram below:
GrogVix [38]
For the answer to the question above, just <span>use similar triangles. 
</span>Here's the equations that I used.

<span>t/h = (x + t) / r </span>
<span>x + t = rt / h </span>
<span>x = rt / h - t 
I hope my answer helped you in your problem, Have a nice day</span>
6 0
3 years ago
Read 2 more answers
If you rotate the point (2, 3) 90 degrees counterclockwise about the origin, what is the image of the point?
AlexFokin [52]
Rotation counterclockwise 90 degrees has the rule

(x,y) -> (-y,x)

So the image is obtained, according to the rule, 
(2,3) -> (-3,2)
4 0
3 years ago
A performer expects to sell $5000 tickets for an upcoming concert. They plan to make a total of $311000 in sales from these tick
Rus_ich [418]

Answer:

Pleaselet me see

Step-by-step explanation:

5 0
2 years ago
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What is the answer to -5+1-5+1​
stellarik [79]

Answer:

the answer is -8

Step-by-step explanation:

U take - 5 and u put one, so it goes -4, then u go 5 down so - 9 and +1 is - 8

8 0
2 years ago
Read 2 more answers
How many positive integers less than 1000 a) aredivisibleby7? b) are divisible by 7 but not by 11? c) are divisible by both 7 an
notsponge [240]

Answer:

a.142 b.130 c.12 d.220 e.208 f.779 g.720

Step-by-step explanation:

How many positive integers less than 1000 (from 1 to 999)

a) are divisible by 7?

999/7=142,71

then there are 142 integers that are divisible by 7

7*1=7

7*2=14

7*3=21

...

7*141=987

7*142=994

b) are divisible by 7 but not by 11?

as 7 and 11 are prime numbers

7*11=77

999/77=12.97

142-12=130

c) are divisible by both 7 and 11?

999/77=12.97

then there are 12 integers that are divisible by both 11 and 7 below 1000

d) are divisible by either 7 or 11?

999/7=142.71

999/11=90.81

then the numbers that are divisible either by 7 or 11 is

142+90-12(the numbers that are counted in both grups 'divisible by 7' and 'divisible by 11')

220

e) are divisible by exactly one of 7 and 11?

[142('divisible by 7')-12('divisible by both')]+[90('divisible by 11')-12('divisible by both')]

208

f) are divisible by neither 7 nor 11?

999('all the positive integers below 1000)-220('are divisible by either 7 or 11')

779

g) have distinct digits?

For evey digit x from 0 to 9

0xx,1xx,2xx,3xx,4xx,5xx,6xx,7xx,8xx,9xx 10 options

xx0,xx1,xx2,xx3,xx4,xx5,xx6,xx7,xx8,xx9 10 options

x0x,x1x,x2x,x3x,x4x,x5x,x6x,x7x,x8x,x9x 10 options

and xxx one option

for each of the first three rows we have to sustract the option in wich the three digits are the same digit.

for the 0 we have to sustract the 000 of the fourth row as it is not a positive number.

10 (different digits)*(9+9+9+1)(different combinations for each number)-1(the 000)=279

999-279=720

8 0
3 years ago
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