2237-400= 1837 hope this helps!
Answer:
k = 10
Step-by-step explanation:
The sum of k terms of a geometric sequence with first term a1 and common ratio r is given by ...
... Sk = a1·(1 -r^k)/(1 -r)
For the given numbers, this is ...
... 118096 = 78732·(1 -(1/3)^k)/(1 -1/3)
Manipulating this to get the term containing k, we have
... 1 -(2/3)(118096/78732) = (1/3)^k
... 1/59049 = (1/3)^k
Taking logarithms, we get
... -log(59049) = -k·log(3)
... log(59049)/log(3) = k = 10
Start by combining LIKE-TERMS. 13b AND 23 are LIKE-TERMS because they have the same variable (B) and numbers. Remember PEMDAS OR Please Excuse My Dear Aunt Sally. (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). There is also FOIL (First, Inside, Outside, Last). Because we will start with Parenthesis(Use the FOIL method because the 56 is part of the parentheses) first, (-56 x b[first part of the set]) = -56b THEN (-56 x [+ {always carry the sign, this shows that it is positive}]1) = -56
Now we have 13b+23b -56b-56
=36b -56b -56
= -20b - 56
This is your final equation because THESE ARE NOT LIKE-TERMS, therefore, they CANNOT be combined
Answer:
a) Arithmetic yₙ = 3*(n - 1) + 13
b) Geometric yₙ = 2*5⁽ⁿ⁻¹⁾
Step-by-step explanation:
240 for # 2 because 6 times 4 times 10 is equal to 240
I am still working on others
