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Mice21 [21]
3 years ago
12

Eddie bought 27 2/5 inches of wire for a home improvement project. How many 12 inches sections can he make from it?

Mathematics
1 answer:
goblinko [34]3 years ago
3 0
Simply divide your wire by 12 and cut off the excess (as it cannot make a full 12-inch section).

27\frac{2}{5}÷12=2\frac{17}{60}

So you have two 12-inch sections and an additional 3.4-inch section.
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2.6 more than the quotient of h and 3 is w
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7 0
3 years ago
Read 2 more answers
Fill in the missing number.<br> 24, 32, _<br> -, 48, 56
Cloud [144]
The answer is 40..........
3 0
3 years ago
Tao uses elimination to solve the following system of linear equations. -2x+4y=162x+2y=8Which ordered pair is a solution to the
Alex_Xolod [135]

The correct answer is the first option.


If you want to use elimination, you can sum the two equations for example, so that the x's simplify:


(-2x+4y)+(2x+2y) = 16+8


6y = 24


y = 4


Plug this value for y in one of the equations to derive the value of x:


2x+2y=8 \implies 2x + 8 = 8 \implies x = 0


So, the solution is (x,y) = (0,4)

8 0
3 years ago
A cone has a height 25 ft and a radius of 7 ft. Is a reasonable that the volume of this cone is 100 ft3? Why or why not?​
Nostrana [21]

Answer:

No

Step-by-step explanation:

the radius squared is 49 times π, which is roughly 3 means the area of the base is roughly 150 ft².

This means that one third of the height cannot be more than 100 / 150 = 2/3 of a foot. That makes the height about 2 ft, much less than the reported 25 ft.

3 0
3 years ago
What’s the pattern of -1, -8, -27, and -64
AURORKA [14]

Hello from MrBillDoesMath!

Answer:

a(n) = (-n)^3  where n = 1,2,3,...


Discussion:

The pattern  1,8,27, 64... is immediately recognizable as the the cube of the positive integers. But this question has a minus sign appearing before  each entry, suggesting we try this:


 - 1  =  (-1)^3

 -8  = (-2)^3

-27  = (-3)^3

-64  = (-4)^3

That's what the problem statement asked for . The answer is equivalently

-1 * (n^3)


Thank you,

MrB

6 0
3 years ago
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