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Sever21 [200]
3 years ago
9

How many times larger is the broadcast area of channel 19 than the broadcast area of channel 36?

Mathematics
1 answer:
GaryK [48]3 years ago
8 0

Answer:

17

Step-by-step explanation:

You will have to subtract 36 and 19 and than you will get 17

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i buy 3 apples to 4 bananas. If I buy 6 more bananas than apples, how many total pieces of fruit did I buy?
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Answer:

42

Step-by-step explanation:

The difference in ratio units is 1, which corresponds to a difference in fruit count of 6. So the total of 7 ratio units must represent 7×6 = 42 pieces of fruit.

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Solve the Problem below
m_a_m_a [10]

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3/4 + 1= 2x - x+1/4

Step-by-step explanation:

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3. Ellie can type 105 words in 3 minutes.
Marta_Voda [28]

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Step-by-step explanation:

Ellie:; 105/3 = 35 wpm

Vivian: 120/4 = 30 wpm

6 0
3 years ago
Read 2 more answers
A shelf has 20 bags of potatoes. Two of the bags have potatoes starting to go bad. The probability of drawing a bag with bad pot
nekit [7.7K]

Probability of drawing bad potatoes = 0.1

The probability of drawing a bag with bad potatoes is less than 1.

The probability of drawing a bag with good potatoes is greater than 0

The probability of drawing a bag with bad potatoes as a decimal .

The probability is 20% which means 20 by hundred , which means there is a chance of being its ok.

probability of bad potatoes = 2/20

=1/10

=0.1

probability of good potatoes = 1- ( probability of bad potatoes)

=1-0.1

=0.9

To learn more about probability

brainly.com/question/173579

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3 0
1 year ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
3 years ago
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