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algol13
3 years ago
10

Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?

Mathematics
2 answers:
Nady [450]3 years ago
6 0
2x+2 \geq 20

2x \geq 18

x \geq 9 

9 \leq x which  is the same with the one above

The answer to your question is C.A number line with a closed circle on 9 and shading to the left. I hope that this is the answer that you were looking for and it has helped you.
Goshia [24]3 years ago
3 0

Answer:

option C

A number line with a closed circle on  9 and shading to the left

Step-by-step explanation:

we have

2(x+1)\geq 20

solve for x

2x+2\geq 20

Subtract 2 both sides

2x+2-2\geq 20-2

2x\geq 18

Divide by 2 both sides

x\geq 9 --------> is equivalent to 9 \leq x

The solution is the interval--------> [9,∞)

All real numbers greater than or equal to 9

A number line with a closed circle on  9 and shading to the right

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Answer:

x = -5 + √65/2 or

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Step-by-step explanation:

-2x² - 5x + 5 = 0

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Here,

a = 2

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Now,

Discriminant

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<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em>= (5)² - 4(2)(-5)

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Then,

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