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algol13
3 years ago
10

Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?

Mathematics
2 answers:
Nady [450]3 years ago
6 0
2x+2 \geq 20

2x \geq 18

x \geq 9 

9 \leq x which  is the same with the one above

The answer to your question is C.A number line with a closed circle on 9 and shading to the left. I hope that this is the answer that you were looking for and it has helped you.
Goshia [24]3 years ago
3 0

Answer:

option C

A number line with a closed circle on  9 and shading to the left

Step-by-step explanation:

we have

2(x+1)\geq 20

solve for x

2x+2\geq 20

Subtract 2 both sides

2x+2-2\geq 20-2

2x\geq 18

Divide by 2 both sides

x\geq 9 --------> is equivalent to 9 \leq x

The solution is the interval--------> [9,∞)

All real numbers greater than or equal to 9

A number line with a closed circle on  9 and shading to the right

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\boxed{ \bold{ \huge{ \boxed{ \sf{25 \: units}}}}}

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Let M ( 9 , -5 ) be ( x₁ , y₁ ) and N ( - 11 , 10 ) be ( x₂ , y₂ )

<u>Finding</u><u> </u><u>the </u><u>distance </u><u>between</u><u> </u><u>these</u><u> </u><u>points</u>

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Hope I helped!

Best regards! :D

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