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algol13
3 years ago
10

Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?

Mathematics
2 answers:
Nady [450]3 years ago
6 0
2x+2 \geq 20

2x \geq 18

x \geq 9 

9 \leq x which  is the same with the one above

The answer to your question is C.A number line with a closed circle on 9 and shading to the left. I hope that this is the answer that you were looking for and it has helped you.
Goshia [24]3 years ago
3 0

Answer:

option C

A number line with a closed circle on  9 and shading to the left

Step-by-step explanation:

we have

2(x+1)\geq 20

solve for x

2x+2\geq 20

Subtract 2 both sides

2x+2-2\geq 20-2

2x\geq 18

Divide by 2 both sides

x\geq 9 --------> is equivalent to 9 \leq x

The solution is the interval--------> [9,∞)

All real numbers greater than or equal to 9

A number line with a closed circle on  9 and shading to the right

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Explanation:
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<span>
Note that in this correct Answer choice "C" given, we have the following arrangement of numbers:
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   </span>→ -0.7, ⅕, 0.35, ⅔ ; 
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We are asked to find the "Answer choice" (or, perhaps, "Answer choices?") given that show a set of numbers arranged in order from "least to greatest"; that is, starting with a value that is the smallest number in the arrangement, and sequentially progressing, in order from least to greatest, with the largest (greatest) number in the arrangement appearing as the last number in the arrangement.
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