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3 years ago

Given a+b=7 and a–b=3, find: 3^a÷3^b

Mathematics

2 answers:

Mama L [17]3 years ago

6 0

Answer:

a= -2 and b=3

Step-by-step explanation:

Step 1) Solve the first equation for a:

a + 3b = 7

a + 3b - 3b = 7 - 3b

a + 0 = 7 - 3b

a = 7 - 3b

Step 2) Substitute(7 - 3b) for a in a second equation and solve for b:

2a = b - 7 becomes:

2(7 - 3b) = b-7

(2 multi.7) - (2 multi.3b)= b-7

14 - 6b = b - 7

14 + 7 - 6b + 6b = b + 6b = b + 6b - 7 +7

21 - 0 = 1b + 6b - 0

21=(1 + 6)b

21 = 7b

21 /7 = 7b/7

3 = 7b/7

3 = b

b = 3

Step 3) Substitute 3 for b in the solution to the first equation at the end of Step 1 and calculate a :

a = 7 - 3b becomes:

a = 7 − ( 3 ⋅ 3)

a = 7 − 9

a = − 2

Lostsunrise [7]3 years ago

6 0

I’m not under standing what you’re asking

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3 years ago

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Marina CMI [18]

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Given a+b=7 and a–b=3, find: 3^a÷3^b ​

Given a+b=7 and a–b=3, find: 3^a÷3^b